Pendulum Period Calculator
Period, length or g of a simple pendulum, exact for wide swings and on other worlds.
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Result
How much slower a wide swing is
Wider swings are slower
On other worlds
How it was worked out
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About the Pendulum Period Calculator
The time a simple pendulum takes to swing there and back, its period, depends on its length and on gravity: T = 2π·√(L ÷ g) for small swings. This calculator finds the period of a pendulum, the length that gives a period, or g from a period you have timed, and it does each exactly for any amplitude, not only for small swings.
Wide swings are slower than the small-angle formula says: about 0.2 % at 10°, 1.7 % at 30° and 18 % at 90°. The exact period comes from the arithmetic–geometric mean (the same as the complete elliptic integral), so it is right up to 179°. A chart and a table show how the period grows with the amplitude, and another table puts the same pendulum on the Moon and the planets.
For a lab, enter the time for 10 or 20 oscillations, the length and the amplitude, and add your uncertainties to get g with its error. With a Pro pass, copy the result or download it as a CSV, or unlock this one result. Without a pass the free preview shows the period, length or g you solve for in full, with the first rows of each table, a marked chart and the first step of the working.
How to use it
- Choose what to find: the period, the length for a period, or g from a measurement.
- Enter the length (from the pivot to the centre of the bob), the period you want, or the time for the oscillations you counted, and the amplitude: the angle it is released from.
- Choose Earth’s gravity, the Moon’s, a planet’s or your own value; for g from a measurement, open “Uncertainties” to add yours.
- Read the answer, the chart, the tables and the working. Copy the result or download the CSV with a Pro pass, or after unlocking this result.
Examples
L = 1 m, g = 9.80665 m/s²
T = 2.0102 s exactly; the small-angle formula gives 2.0064 s, 0.19 % short
T = 2 s (one second each way), small swings, on Earth
L = g·(T ÷ 2π)² = 99.36 cm; for 30° swings it must be 95.99 cm
L = 75.000 cm, T = 1.7357 s, a small amplitude
g = 4π²·L ÷ T² = 9.8281 m/s²
10 oscillations in 20.06 s ± 0.2 s, L = 1 m ± 1 mm, released from 5°
T = 2.006 s; g = 9.82 ± 0.2 m/s² (9.8107 m/s² without the amplitude correction, which a 5° swing needs: it is slower than the small-angle formula says)
g = 1.62 m/s², small swings
T = 4.937 s, about 2.5 times as long as on Earth
Released level with the pivot (a rigid rod)
T = 1.1803 × the small-angle period: 18 % slower
Common uses
- Physics labs: g from a timed pendulum, with the amplitude correction and the uncertainty
- Homework on simple harmonic motion and the small-angle approximation
- Choosing the length of a pendulum for a clock, a metronome or a demonstration
- Seeing how much the small-angle formula misses for wide swings
- Comparing the same pendulum on the Moon, Mars or Jupiter
The formulas
- Small swings: T₀ = 2π·√(L ÷ g), f = 1 ÷ T; good to 0.5 % below about 15°, and the period does not depend on the mass
- Any amplitude θ₀: T = T₀ ÷ M(1, cos(θ₀ ÷ 2)), where M is the arithmetic–geometric mean: start with a = 1 and b = cos(θ₀ ÷ 2), and replace them by their average and their geometric mean, √(a·b), until they agree. It equals T = (2T₀ ÷ π)·K(sin(θ₀ ÷ 2)), with K the complete elliptic integral of the first kind
- The series T ≈ T₀·(1 + θ₀²/16 + 11θ₀⁴/3072 + …), θ₀ in radians: close for small swings, too low for wide ones (the chart shows both)
- Length for a period: L = g·(T·M ÷ 2π)²
- g from a period: g = 4π²·L ÷ (M·T)², with T the time measured ÷ the oscillations counted: a wide swing is slower, so the small-angle 4π²·L ÷ T² reads g too low
- Uncertainty: δg ÷ g = √((δL ÷ L)² + (2·δT ÷ T)²); the period counts twice because g goes with 1 ÷ T²
- At the bottom: v = √(2·g·L·(1 − cos θ₀)), from the drop L·(1 − cos θ₀)
Why wide swings are slower
The small-angle formula treats the pull back to the middle as if it grew in step with the angle, but it grows with sin θ, which falls behind the angle as the swing widens. A wide swing is pulled back more gently than the formula assumes, so it takes longer. The exact period is only a little longer for small swings (0.19 % at 10°, 0.43 % at 15°), and the gap grows quickly: 1.7 % at 30°, 7.3 % at 60°, 18 % at 90°, and about 2.4 times as long at 170°.
Above 90° a string goes slack on the way down, so such swings need a light, rigid rod.
Measuring g with a pendulum
- Measure the length from the pivot to the centre of the bob, and keep the string much longer than the bob.
- Release it from a small angle, 5° to 10°, or enter the amplitude so the calculator corrects for it.
- Time 10 or 20 full oscillations, there and back each, and let the calculator divide: the stopwatch’s start and stop errors then spread over all of them.
- Start timing as the bob passes the lowest point, where it moves fastest and the moment is easiest to see.
- Repeat with a few lengths: T² against L is a straight line through zero with a slope of 4π² ÷ g.
Sources
- OpenStax, University Physics Volume 1, §15.4 Pendulums: T = 2π·√(L ÷ g) for angles below about 15° and Example 15.3, measuring g (CC BY 4.0)
- Pendulum (mechanics)): the exact period with the complete elliptic integral, its arithmetic–geometric-mean form and the series in θ₀
- R. A. Nelson and M. G. Olsson, The pendulum — Rich physics from a simple system, American Journal of Physics: the corrections needed to measure g accurately with a pendulum
- NASA JPL Solar System Dynamics: planetary physical parameters: the surface gravity of the planets
Limitations
- A simple pendulum: a small heavy bob on a light string or rod. A swinging bar, a door or a large bob is a physical pendulum, whose period depends on how its mass is spread.
- Air resistance and friction at the pivot are ignored, so the amplitude never dies down here; real swings shrink slowly, which shortens the period a little.
- Gravity differs a little from place to place on Earth (about 9.78 to 9.83 m/s²); choose 9.80665 m/s² or enter your local value.
- Swings wider than 90° need a rigid rod; a string goes slack.
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Frequently asked questions
What do I get without a pass?
Without a pass, Pendulum Period Calculator shows the period, length or g you solve for in full, with the first rows of each table, a marked chart and the first step of the working. Until you unlock it, the result can’t be downloaded or copied. A Pro, Premium or Ultimate pass, a one-time payment that never renews, unlocks the full result. The pricing page lists the passes and their prices.
What is the formula for the period of a pendulum?
For small swings T = 2π·√(L ÷ g). A 1 m pendulum on Earth has T = 2π × √(1 ÷ 9.80665) = 2.006 s. For a wider swing the period is longer: the calculator divides by the arithmetic–geometric mean of 1 and cos(θ₀ ÷ 2), which gives 2.0102 s at 10°.
How long is a pendulum with a period of 2 seconds?
L = g·(T ÷ 2π)² = 9.80665 × (2 ÷ 2π)² = 0.9936 m, just under a metre. This is the seconds pendulum of old clocks: each swing, one way, takes one second.
Does the mass of the bob change the period?
No. A heavier bob needs more force to move, and gravity pulls it harder in the same proportion, so the period depends only on the length, gravity and the amplitude.
When is the small-angle formula good enough?
Below about 15° it is within 0.5 % (0.19 % at 10°, 0.43 % at 15°). At 30° it is 1.7 % short, and at 90° 15 % short (the exact period is 18 % longer), so for wide swings use the exact period.
How do I find g with a pendulum?
Time 10 or 20 oscillations, divide to get the period T, measure the length L, and g = 4π²·L ÷ T². OpenStax’s example: 75.000 cm and 1.7357 s give 9.8281 m/s². Choose “g from a measurement” to include the amplitude correction and your uncertainties.
How does a pendulum swing on the Moon?
Slower: with g = 1.62 m/s² a 1 m pendulum has a period of 4.937 s, about 2.5 times as long as on Earth, because the period goes with 1 ÷ √g.