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Centripetal Force Calculator

F = mv²/r from speed, rpm or period, plus the friction or banking a curve needs.

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Calculate

The inward force that keeps something moving in a circle: F = m v² ÷ r.

Solve for
The motion as
Centripetal force —

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    About the Centripetal Force Calculator

    Anything moving in a circle is accelerating towards the centre, even at a steady speed, because its direction keeps changing. The net inward force that does it is the centripetal force: F = m v² ÷ r = m ω² r, supplied by whatever holds the object on its path — a string’s tension, a road’s friction, a planet’s gravity. This calculator solves it for the force, the mass, the radius or the motion, with the motion given as a speed, a rotation rate in rpm or rad/s, or a period, and gives the centripetal acceleration (also as a multiple of g), the angular velocity, the period and the frequency.

    For a car on a curve it gives, on a flat road, the least tyre friction coefficient a speed needs, the top speed for a given grip or the tightest radius; on a banked road, the ideal angle at which no friction is needed; and on a banked road with friction, the slowest and fastest speeds at which the car does not slide.

    Without a pass, the free preview shows the value you solve for in full, with the first step of the working; the other figures, the whole working and Copy result need a Pro pass, or unlocking this one result.

    How to use it

    1. Choose Circular motion or Car on a curve.
    2. For circular motion, pick what to solve for and how the motion is given: a speed, a rotation rate (rpm, rev/s, rad/s) or a period. Type the other values and choose their units.
    3. For a curve, pick a flat road, a banked road, or a banked road with friction, then what to find. Choose a friction coefficient from the list or type one, and the gravity (standard or a textbook rounding).
    4. Read the answer, the other figures and the working. Copy the result with a Pro pass, or after unlocking this result.

    Examples

    A car on a flat curve
    Input
    900 kg at 25.00 m/s round a 500.0 m radius
    Result
    F = 1,125 N; tyre friction μs ≥ 0.13 (with g = 9.8)

    OpenStax University Physics Vol. 1, Example 6.15.

    A banked curve
    Input
    100.0 m radius banked at 31.0°
    Result
    Ideal speed 24.3 m/s, about 87.5 km/h

    OpenStax Example 6.16.

    A washing machine’s spin
    Input
    Drum radius 25 cm at 1,200 rpm
    Result
    a = r ω² = 3,948 m/s² = 403 g
    A ball on a string
    Input
    0.5 kg on 1.2 m, twice a second
    Result
    F = 94.7 N, speed 15.1 m/s
    Top speed on a dry curve
    Input
    Flat 50 m radius, μs = 1.0 (rubber on dry concrete)
    Result
    v = √(μ r g) = 22.1 m/s (79.7 km/h)
    A banked curve with friction
    Input
    100 m radius at 31°, μs = 0.5
    Result
    No sliding between 8.7 and 39.3 m/s (31 and 141 km/h)
    Earth around the Sun
    Input
    5.97 × 10²⁴ kg, 1.496 × 10⁸ km, one year
    Result
    a = 0.00593 m/s²; the Sun’s gravity supplies F = 3.54 × 10²² N

    Common uses

    • Physics homework on uniform circular motion, centripetal force and acceleration, with the working shown.
    • Centrifuges, spin dryers and rotors: the g-force at a radius and rpm.
    • Cars, bikes and trains on curves: the grip needed, the safe speed or the banking angle — as physics estimates.
    • Orbits, swings, fairground rides and objects on strings.

    The formulas

    • Centripetal force: F = m v² ÷ r = m ω² r, with v = ω r.
    • Centripetal acceleration: a = v² ÷ r = ω² r, in g when divided by 9.80665 m/s².
    • Rotation: ω = 2π ÷ T = 2π f, and 1 rpm = 2π/60 rad/s. Doubling the speed (or the rpm) needs four times the force.
    • Rearranged: m = F r ÷ v², r = m v² ÷ F, v = √(F r ÷ m); with ω, r = F ÷ (m ω²) and ω = √(F ÷ (m r)).

    A car on a curve

    • Flat road: friction supplies the inward force, so the least static friction coefficient is μs = v² ÷ (r g), the top speed √(μs r g) and the tightest radius v² ÷ (μs g).
    • Banked road, no friction: the slope of the road supplies it at one speed, where tan θ = v² ÷ (r g) (OpenStax Eq. 6.4).
    • Banked road with friction: faster than that, friction acts down the slope; slower, up it. The limits are v_max = √(r g (sin θ + μ cos θ) ÷ (cos θ − μ sin θ)) (no limit once μ ≥ 1 ÷ tan θ) and v_min = √(r g (sin θ − μ cos θ) ÷ (cos θ + μ sin θ)) (zero once tan θ ≤ μ: the car can stand still).
    • The mass cancels in all of these; it is needed only for the forces.

    Friction coefficients

    The list uses the approximate static coefficients of OpenStax Table 6.1: rubber on dry concrete 1.0, rubber on wet concrete 0.5–0.7, shoes on ice 0.1. Real tyre grip depends on the tyre, its temperature and wear, the surface, water, speed and load, so treat results as estimates and leave a margin.

    Sources

    Limitations

    • Uniform circular motion: a constant speed on a circle. Speeding up or slowing down adds a forward or backward acceleration.
    • The car is treated as a point on the road: weight transfer, rollover, aerodynamic downforce and tyre slip angles are not modelled.
    • Friction is the simple maximum μN; real tyres behave less neatly near their limit.
    • Physics estimates only, not road or vehicle design: real roads are designed to standards with safety margins.

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    Frequently asked questions

    What do I get without a pass?

    Without a pass, Centripetal Force Calculator shows the value you solve for in full, with the first step of the working; every other figure is hidden. Until you unlock it, the result can’t be copied. A Pro, Premium or Ultimate pass, a one-time payment that never renews, unlocks the full result. The pricing page lists the passes and their prices.

    What is the formula for centripetal force?

    F = m v² ÷ r, or F = m ω² r with the angular velocity ω in rad/s. A 900 kg car at 25 m/s round a 500 m curve needs 900 × 25² ÷ 500 = 1,125 N of inward force, supplied by tyre friction.

    What is the difference between centripetal and centrifugal force?

    Centripetal force is the real inward force (tension, friction, gravity) that keeps something on a curved path. Centrifugal force is the outward push you seem to feel from inside the turning object: it is the effect of your own inertia carrying you straight on, not an extra force from outside.

    How do I convert rpm to g-force?

    Find ω = rpm × 2π ÷ 60, then a = r ω², and divide by 9.80665 m/s². A point 25 cm from the axis at 1,200 rpm has ω = 125.7 rad/s, a = 0.25 × 125.7² = 3,948 m/s², which is 403 g.

    What friction does a car need to take a curve?

    On a flat road at least μs = v² ÷ (r g). At 25 m/s (90 km/h) round a 500 m radius that is 25² ÷ (500 × 9.8) = 0.13 — easy on dry concrete (about 1.0), but a curve that needs more than about 0.5 can be too much on a wet road.

    What is the ideal banking angle for a curve?

    tan θ = v² ÷ (r g), so the road surface alone turns the car with no sideways friction. For 24.3 m/s round a 100 m radius it is 31°, as in OpenStax Example 6.16. Banking also widens the range of safe speeds when friction helps.

    Why does doubling the speed quadruple the centripetal force?

    Because the force grows with v²: twice the speed means four times the inward force (and acceleration) on the same radius. That is why a curve that is safe at 50 km/h can be dangerous at 100 km/h.

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