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Mohr's Circle Calculator

Principal stresses, maximum shear and any rotated plane, drawn on the circle.

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Stress state

Gives the factor of safety by von Mises and by Tresca. Leave empty to skip.
Tension positive, compression negative.
Positive when it acts in +y on the face whose outward normal points in +x.
°
The stresses on that plane are X′ (and Y′, 90° on) on the circle, at 2θ from the x face.

Result

Principal stresses —

    How it was worked out

      Next steps Done. What next?

      All engineering & electronics calculators

      Results are estimates from the formulas shown, not a professional design or certification. Have a qualified engineer verify anything safety-critical (structures, electrical installations, gas or pressure systems).

      About the Mohr's Circle Calculator

      Enter the stresses on an element — σx, σy and τxy for plane stress — and get the principal stresses σ1 and σ2 with the direction of each, the maximum in-plane shear stress and the planes it acts on, the stresses on a plane turned to any angle θ, the absolute maximum shear (including the out-of-plane one), and the von Mises and Tresca equivalent stresses with factors of safety against a yield strength. Everything is drawn on an interactive Mohr's circle: move the angle and the rotated plane travels round it.

      For a general stress state, switch to the 3D stress tensor: the six components give the three principal stresses (the eigenvalues of the tensor), their directions, the invariants, the maximum shear and the equivalent stresses, with all three Mohr's circles. Results are estimates from elasticity theory for checking and learning, not a professional design.

      Without a pass, the free preview draws the circle of your own stresses with a watermark and no numbers on it, and shows the names of the table’s first rows, with the principal stresses, the working and every other figure hidden; the full result, Copy result, the CSV table and the PNG diagram come with a Pro pass.

      How to use it

      1. Choose plane stress (2D) or the 3D stress tensor, and the stress unit. Changing the unit converts the numbers already typed.
      2. Type the stresses: tension positive, compression negative. τxy is positive when it acts in the +y direction on the face whose outward normal points in +x (the usual textbook convention).
      3. Read the principal stresses, then the circle. Drag the angle θ slider (or type an angle) to see the normal and shear stress on any plane; X′ and Y′ show it on the circle, twice the angle round from the x face.
      4. Add the yield strength to compare the von Mises and Tresca stresses with it, and check the notes — they say when the largest shear acts out of the plane.
      5. Copy the result, download the table as CSV or the diagram as a PNG for a report — with a Pro pass, or after unlocking this result.

      Examples

      Textbook plane-stress example
      Input
      σx = 50 MPa, σy = −10 MPa, τxy = 40 MPa
      Result
      Centre 20 MPa, radius 50 MPa: σ1 = 70 MPa at θp = 26.57°, σ2 = −30 MPa at 116.57°, τmax = 50 MPa at θs = −18.43° with σ = 20 MPa on those planes; von Mises 88.88 MPa, Tresca 100 MPa

      A worked example of chapter 7 of Beer and Johnston’s Mechanics of Materials, with the same answers.

      Stresses on a plane at 30°
      Input
      The same element, θ = 30° counter-clockwise from x
      Result
      σx′ = 20 + 30 cos 60° + 40 sin 60° = 69.64 MPa, σy′ = −29.64 MPa, τx′y′ = −30 sin 60° + 40 cos 60° = −5.98 MPa
      Pure shear (a shaft in torsion)
      Input
      σx = σy = 0, τxy = 50 MPa
      Result
      σ1 = 50 MPa and σ2 = −50 MPa at 45°; von Mises 86.60 MPa (√3 × 50), Tresca 100 MPa
      Biaxial tension (a pressure vessel wall)
      Input
      σx = 100 MPa (hoop), σy = 50 MPa (axial), τxy = 0
      Result
      In-plane τmax is only 25 MPa, but with σ3 = 0 the absolute maximum shear is σ1/2 = 50 MPa, out of the plane

      Common uses

      • Finding the principal stresses and the maximum shear at a point of a beam, shaft or plate from a strain-gauge rosette or a hand calculation
      • Combining bending and torsion in a shaft (σx from bending, τxy from torque) and checking the von Mises stress
      • Reading the stresses on a weld, a glued joint or a grain direction at a given angle
      • Getting the principal stresses and directions of a full stress tensor from a finite-element result
      • Checking Mohr’s circle homework, with the working and the diagram

      Formulas used

      • Centre and radius: σ_avg = (σx + σy)/2, R = √(((σx − σy)/2)² + τxy²)
      • Principal stresses: σ1,2 = σ_avg ± R; direction of σ1: θp = ½ atan2(2τxy, σx − σy), counter-clockwise from x
      • Maximum in-plane shear: τmax = R on the planes at θs = θp − 45° (and +45°), where the normal stress is σ_avg
      • Any plane: σx′ = σ_avg + (σx − σy)/2·cos 2θ + τxy·sin 2θ; τx′y′ = −(σx − σy)/2·sin 2θ + τxy·cos 2θ; σy′ = σx + σy − σx′
      • Absolute maximum shear (plane stress, σ3 = 0): half the spread of σ1, σ2 and 0
      • von Mises: σ_vm = √(σ1² − σ1σ2 + σ2²) = √(σx² − σxσy + σy² + 3τxy²); Tresca: σmax − σmin
      • 3D: the principal stresses are the eigenvalues of the symmetric stress tensor, the roots of σ³ − I1σ² + I2σ − I3 = 0; σ_vm = √(½[(σ1 − σ2)² + (σ2 − σ3)² + (σ3 − σ1)²]); τ_oct = (√2/3)σ_vm

      Sign convention on the circle

      Tension is positive. On the circle the shear stress is plotted positive downward, and the x face is the point X = (σx, τxy), the y face Y = (σy, −τxy). With this convention a counter-clockwise turn of the element by θ is a counter-clockwise turn of 2θ on the circle, as in Hibbeler’s Mechanics of Materials; it draws the same picture as Beer and Johnston’s rule that a shear stress tending to turn the element clockwise is plotted above the axis. Angles in the results are measured counter-clockwise from the x axis.

      Which equivalent stress to use

      For ductile metals, yielding is predicted when the von Mises (distortion-energy) stress reaches the tensile yield strength; the Tresca (maximum-shear-stress) criterion is slightly more conservative, by up to about 15 %. Brittle materials such as cast iron and concrete fail by other criteria (Coulomb–Mohr, modified Mohr), which compare σ1 and σ3 with the tensile and compressive strengths separately.

      Sources

      • Mohr, O., the paper that introduced the circle, Der Civilingenieur, volume 28
      • Beer, Johnston, DeWolf and Mazurek, Mechanics of Materials, chapter 7 (transformations of stress)
      • Budynas and Nisbett, Shigley's Mechanical Engineering Design, chapter 3 (Mohr's circle, three-dimensional stress) and chapter 5 (von Mises and Tresca)

      Limitations

      • Linear elasticity and a single point: the stresses you enter are assumed to be known; the calculator does not work them out from loads.
      • Plane stress assumes no stress perpendicular to the plane (σz = τxz = τyz = 0); use the 3D tensor otherwise.
      • von Mises and Tresca are yield criteria for ductile, isotropic materials. They do not apply to brittle materials, composites or fatigue, and they do not include stress concentrations.
      • An estimate for learning and checking — not a professional design. Have a qualified engineer verify anything safety-critical.

      Privacy

      Everything happens in your browser. What you enter or open here is not uploaded or stored by MySmartCoPilot.

      Frequently asked questions

      What do I get without a pass?

      Without a pass, Mohr's Circle Calculator shows the circle with a MySmartCoPilot watermark and the names of the table’s first rows (up to 3), with the principal stresses, the working and every figure hidden. Until you unlock it, the result can’t be downloaded or copied. A Pro, Premium or Ultimate pass, a one-time payment that never renews, unlocks the full result. The pricing page lists the passes and their prices.

      How do you draw Mohr's circle?

      Plot the x face at (σx, τxy) and the y face at (σy, −τxy), with shear positive downward. The line between them is a diameter: its middle is the centre σ_avg = (σx + σy)/2 and half its length the radius R. The circle crosses the σ axis at the principal stresses σ_avg ± R.

      How do I find the principal stresses?

      σ1,2 = (σx + σy)/2 ± √(((σx − σy)/2)² + τxy²). For σx = 50, σy = −10 and τxy = 40 MPa that is 20 ± 50, so σ1 = 70 MPa and σ2 = −30 MPa. The principal planes carry no shear stress.

      Why is the angle doubled on the circle?

      The stress-transformation equations depend on 2θ (cos 2θ and sin 2θ), so turning the element by θ moves its point by 2θ round the circle. The principal planes, 90° apart on the element, are 180° apart on the circle.

      What is the difference between maximum in-plane and absolute maximum shear stress?

      The in-plane maximum is the radius R. A plane-stress element also has σ3 = 0 out of the plane, so when σ1 and σ2 have the same sign the largest shear is σ1/2 (or |σ2|/2), on planes tilted out of the plane — larger than R. The calculator shows both.

      How is the von Mises stress calculated?

      For plane stress σ_vm = √(σ1² − σ1σ2 + σ2²), or directly √(σx² − σxσy + σy² + 3τxy²). In 3D, σ_vm = √(½[(σ1 − σ2)² + (σ2 − σ3)² + (σ3 − σ1)²]). A ductile material is predicted to yield when it reaches the yield strength.

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