Motor Torque, Power & Speed Calculator
Torque ↔ power ↔ speed, slip and motor current — with every formula shown.
How it was calculated
In every unit
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Induction motor: synchronous speed and slip
| Poles | Synchronous speed at 50 Hz |
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Current estimate
Gearbox
Results are estimates from the formulas shown, not a professional design or certification. Have a qualified engineer verify anything safety-critical (structures, electrical installations, gas or pressure systems).
About the Motor Torque, Power & Speed Calculator
Torque, power and speed are tied together by one equation: P = T × ω, where ω is the shaft speed in radians per second. Enter any two of them — shaft power in kW, W, hp or PS, torque in N·m, lbf·ft, kgf·m and four other units, speed in rpm, rad/s or rev/s — and the calculator gives the third, converts it into every unit and shows the working.
For AC induction motors it also finds the synchronous speed from the poles and supply frequency, the slip and the rotor frequency. It estimates the full-load current from the voltage, efficiency and power factor, and the starting current for direct-on-line, star–delta and autotransformer starts. These are planning estimates: take the current for cables and protection from the motor nameplate.
How to use it
- Choose what to solve for — torque, power or speed — and enter the other two with their units. A motor’s rated power is its shaft output (the nameplate kW or hp) and its rated speed is the nameplate rpm.
- Read the result and its conversions. How it was calculated shows ω = 2π × n ÷ 60 and the shortcut forms T = 9549.3 × P ÷ n (kW, N·m) and T = 5252.1 × P ÷ n (hp, lbf·ft).
- For an induction motor, pick the supply frequency and the number of poles — or leave Auto to work the poles out from the speed — to see the synchronous speed, slip and rotor frequency.
- Under Current estimate, enter the supply, voltage, efficiency and power factor from the nameplate, and the locked-rotor current ratio (I_A/I_N) or NEMA code letter, to estimate the full-load and starting current.
- Add a gearbox ratio and efficiency if the motor drives one. Copy result copies everything, formulas included.
Examples
Solve for torque: 7.5 kW, 1,450 rpm
T = 9549.3 × 7.5 ÷ 1450 = 49.39 N·m (36.43 lbf·ft)
Solve for torque: 10 hp, 1,750 rpm
T = 5252.1 × 10 ÷ 1750 = 30.01 lbf·ft (40.69 N·m)
Rated speed 1,450 rpm, 50 Hz
n_s = 120 × 50 ÷ 4 = 1,500 rpm · slip = (1500 − 1450) ÷ 1500 = 3.33% · rotor frequency 1.67 Hz
7.5 kW, 400 V three-phase, efficiency 90%, PF 0.85, I_A/I_N = 7
I = 8,333 W ÷ (1.732 × 400 × 0.85) = 14.15 A · direct on line ≈ 99.1 A · star–delta ≈ 33.0 A
49.39 N·m at 1,450 rpm, gearbox 10:1 at 95%
145 rpm and 469.2 N·m at the output shaft
The formulas
- Power, torque and speed: P = T × ω with ω = 2π × n ÷ 60 (P in W, T in N·m, n in rpm)
- SI shortcut: T [N·m] = 9549.3 × P [kW] ÷ n [rpm]; 9549.3 is 60,000 ÷ 2π
- US shortcut: T [lbf·ft] = 5252.1 × P [hp] ÷ n [rpm]; 5252.1 is 33,000 ÷ 2π, because 1 hp is 33,000 ft·lbf per minute
- Synchronous speed: n_s = 120 × f ÷ p (f in Hz, p the number of poles)
- Slip: s = (n_s − n) ÷ n_s; rotor frequency f_r = s × f
- Full-load current: I = P_out ÷ (η × √3 × V × PF) three-phase, P_out ÷ (η × V × PF) single-phase, P_out ÷ (η × V) DC
- Gearbox: n_out = n ÷ i and T_out = T × i × η_g
Units
Horsepower here is mechanical horsepower, 550 ft·lbf/s = 745.7 W; PS (metric horsepower, also CV) is 75 kgf·m/s = 735.5 W. For torque, 1 lbf·ft = 1.3558 N·m, 1 lbf·in = 0.11298 N·m, 1 kgf·m = 9.80665 N·m, 1 kgf·cm = 0.0980665 N·m and 1 ozf·in = 0.0070616 N·m — kgf·cm and ozf·in are common on small DC, servo and stepper motors. All factors follow from the exact foot (0.3048 m), pound-force (4.448 221 615 260 5 N) and standard gravity (9.806 65 m/s²).
Induction motor speed and slip
The rotor of an induction motor turns a little slower than the magnetic field. The field turns at the synchronous speed n_s = 120 × f ÷ p: 3,000, 1,500, 1,000 and 750 rpm for 2, 4, 6 and 8 poles on 50 Hz, and 3,600, 1,800, 1,200 and 900 rpm on 60 Hz. The difference is the slip, a few percent at full load for standard motors and more for small ones — so a 4-pole motor is rated around 1,450 rpm on 50 Hz or 1,750 rpm on 60 Hz. With Auto, the calculator picks the most poles whose synchronous speed is still above the speed you entered.
Starting current and starting methods
Started direct on line (DOL), an induction motor draws its locked-rotor current until it speeds up. IEC motor datasheets give it as a multiple of the rated current (I_A/I_N or I_s/I_n), often between 5 and 8; NEMA motors carry a code letter for the locked-rotor kVA per horsepower (NEMA MG 1; the same ranges are in NEC Table 430.7(B)).
- Star–delta: the windings start in star, so the line current and the starting torque are one third of DOL. The motor needs all six winding ends and a delta rating at the supply voltage
- Autotransformer at tap x: line current and torque are both x² of DOL — 42% at a 65% tap
- Soft starters and drives limit the current to a setting; see their manuals
Sources
- IEC 60034-1:2022, Rotating electrical machines — Part 1: Rating and performance
- NEMA MG 1, Motors and Generators — locked-rotor code letters
- NFPA 70, National Electrical Code: Table 430.7(B) (code letters), 430.6(A)(1) (table currents for conductors and short-circuit protection) and 430.6(A)(2) (nameplate current for overload protection)
- NIST Special Publication 811 (2008), Appendix B — conversion factors for horsepower, pound-force and kilogram-force
Limitations
- Full-load current is estimated from the efficiency and power factor you enter; the real current depends on the motor and how hard it is loaded. Set protection from the nameplate current.
- Starting currents assume a stiff supply: a weak supply lowers both the current and the voltage at the motor. The autotransformer figures ignore its magnetising current.
- Synchronous speed and slip apply to induction (asynchronous) motors. Synchronous, permanent-magnet, brushless DC and DC motors set their speed in other ways.
- Gearbox efficiency varies with load, speed and type (worm gears especially) — use the value from the gearbox datasheet.
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Frequently asked questions
How do I convert kW and rpm to torque?
Divide power by angular speed: T = P ÷ (2π × n ÷ 60). With kW and rpm this is T [N·m] = 9549.3 × P ÷ n, so a 7.5 kW motor at 1,450 rpm gives 9549.3 × 7.5 ÷ 1450 = 49.39 N·m.
What is the 5252 rule?
In US units, torque in lbf·ft equals 5252 × horsepower ÷ rpm. The 5252 is 33,000 ÷ 2π, because one horsepower is 33,000 ft·lbf per minute. It is also why torque and horsepower curves in lbf·ft and hp always cross at 5,252 rpm.
How do I find the number of poles of a motor?
Take the synchronous speed just above the rated speed. On 50 Hz, 2,950 rpm means 2 poles (3,000 rpm), 1,450 rpm means 4 poles (1,500 rpm) and 970 rpm means 6 poles (1,000 rpm). On 60 Hz the synchronous speeds are 3,600, 1,800, 1,200 and 900 rpm.
What is slip in an induction motor?
How far the rotor lags behind the synchronous speed, as a fraction: s = (n_s − n) ÷ n_s. It grows with load. A 4-pole motor at 1,450 rpm on 50 Hz has 3.33% slip, and its rotor currents alternate at 0.0333 × 50 = 1.67 Hz.
How much current does a motor draw when it starts?
Started direct on line it draws its locked-rotor current — use the datasheet’s I_A/I_N or the NEMA code letter. A 7.5 kW, 400 V motor with I_A/I_N = 7 and a 14.15 A full-load current draws about 99 A; star–delta starting cuts that, and the starting torque, to one third.
Is a motor’s rated power its input or its output?
The nameplate kW or hp is the mechanical output at the shaft. The electrical input is larger by the efficiency: a 7.5 kW motor that is 90% efficient takes 7.5 ÷ 0.9 = 8.33 kW from the supply.