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IT Support & Help Desk Fundamentals  Module 3 – Hardware and peripherals

Power supplies, UPS sizing and battery safety

Size a UPS by VA, watts and power factor, estimate honest runtime, choose a surge protector or UPS, and handle a swollen lithium-ion battery safely.

  • Intermediate
  • 25 minutes
  • Examples run with Python 3.14.8 and Pyodide 314.0.7
  • By MySmartCoPilot
Free lesson, Pro answers: 25 minutes
Free: the whole lesson. With a pass: the model answers to its 2 interview questions.

What you will learn

  • Explain what a desktop power supply does, why it stays sealed, and the parts of its label a help desk reads
  • Distinguish standby, line-interactive and double conversion UPS designs from the path they take to a device
  • Size a UPS for a small-office load using VA, watts and the power factor the inverter sees
  • Estimate an honest UPS runtime after inverter loss, battery age and the Peukert effect
  • Follow a stop-work routine for a swollen lithium-ion battery and route it to an authorised recycler
What you’ll learn

What you will learn

  • Explain what a desktop power supply does, why it stays sealed, and the parts of its label a help desk reads
  • Distinguish standby, line-interactive and double conversion UPS designs from the path they take to a device
  • Size a UPS for a small-office load using VA, watts and the power factor the inverter sees
  • Estimate an honest UPS runtime after inverter loss, battery age and the Peukert effect
  • Follow a stop-work routine for a swollen lithium-ion battery and route it to an authorised recycler
On this page

A 3-year-old 650 VA UPS carries a 357 W office for 5 minutes before it drops. The desktops save their files in time, but the Wi-Fi router and the fibre ONT go dark with them, so cloud sync, voice calls and the alert that tells the team the mains are back all stop. Both outcomes come from a label the help desk could have read: VA, watts, battery energy and the three losses that pull the real runtime well below the sticker.

You will read a desktop power supply, pick between standby, line-interactive and double conversion UPS designs, size a UPS from a load’s watts and power factor, estimate honest runtime after inverter loss and battery age, choose between a surge protector and a UPS, and handle a swollen lithium-ion battery safely under India’s Battery Waste Management Rules.

A desktop power supply, from the socket to the board

A desktop power supply unit: The box inside a desktop computer that turns the mains voltage into +12 V, +5 V and +3.3 V rails for the board, drives and cards. Its short name is PSU. turns the mains voltage into the three steady low-voltage rails every part of a computer needs: +12 V for the processor, graphics card and drives, +5 V for older peripherals and USB ports, and +3.3 V for the chipset, memory modules and most M.2 cards. The label on the side of a modern retail unit names its rated total in watts and gives the amps each rail can supply, with an 80 Plus badge for the efficiency band it has been tested at (Bronze, Silver, Gold, Platinum and Titanium from the lowest to the highest). The watts figure is a cap on the sum across every rail at a given moment, not the sum of each rail at full load, so the arithmetic in a lesson example overshoots on paper and the real draw stays within the cap.

A 500 W PSU and the office desktop that uses 138 W of it Python · power_rails/power_rails.py
# A labelled 500 W PSU splits that budget across three rails. The program prints each rail's share, then adds up a
# typical office desktop's draw and compares it with the PSU's total. Numbers from a mid-range retail label; a lesson
# fixture, not a specific product. Standard library only, deterministic.

rails = [
    ("+12 V", 12.0, 36.0),   # the heavy rail: CPU, GPU, drives
    ("+5 V",   5.0, 20.0),   # legacy devices and USB
    ("+3.3 V", 3.3, 15.0),   # chipset, DIMMs, M.2 power
]

print(f"{'rail':<8}{'volts':>7}{'amps':>7}{'watts':>8}")
total_rated = 0.0
for name, volts, amps in rails:
    watts = volts * amps
    total_rated += watts
    print(f"{name:<8}{volts:>7.1f}{amps:>7.1f}{watts:>8.1f}")
print(f"{'sum':<8}{'':>7}{'':>7}{total_rated:>8.1f}")
print(f"PSU label total: 500.0 W (the label is a cap, not the sum of every rail at once)")

load = [
    ("CPU under a build",    80.0),
    ("integrated graphics", 15.0),
    ("NVMe SSD",             6.0),
    ("one SATA SSD",         3.0),
    ("DDR5 memory, 32 GB",   8.0),
    ("case and CPU fans",    6.0),
    ("motherboard",         18.0),
    ("USB keyboard+mouse",   2.0),
]
total_load = sum(w for _, w in load)
print()
print(f"{'component':<24}{'watts':>8}")
for name, watts in load:
    print(f"{name:<24}{watts:>8.1f}")
print(f"{'total':<24}{total_load:>8.1f}")
print(f"headroom at 500 W PSU: {500.0 - total_load:.1f} W, so a GPU drawing more than that cannot be added")

Output

rail      volts   amps   watts
+12 V      12.0   36.0   432.0
+5 V        5.0   20.0   100.0
+3.3 V      3.3   15.0    49.5
sum                      581.5
PSU label total: 500.0 W (the label is a cap, not the sum of every rail at once)

component                  watts
CPU under a build           80.0
integrated graphics         15.0
NVMe SSD                     6.0
one SATA SSD                 3.0
DDR5 memory, 32 GB           8.0
case and CPU fans            6.0
motherboard                 18.0
USB keyboard+mouse           2.0
total                      138.0
headroom at 500 W PSU: 362.0 W, so a GPU drawing more than that cannot be added

Recorded with Python 3.14.8 on macOS 26 arm64. To run it yourself: mise exec python@3.14.8 -- python3 power_rails.py

The run shows a 138 W budget for a modern office PC without a dedicated graphics card: a processor, memory, two drives, fans, a motherboard and a keyboard and mouse account for every watt, so a 500 W unit leaves 362 W of headroom for a card the user might add later. The 80 Plus Bronze band means the PSU draws about 180 W from the wall to deliver those 138 W to the computer at 20 % load, 175 W at 50 % load, and so on; higher bands narrow the loss, which matters most for machines that run day and night.

Autosensing supplies accept any mains voltage from 100 V to 240 V, so the same unit works in India and in a country with 110 V service without a switch, while older units carry a red slider marked 115/230 V that must match the country or the next power-on becomes an invoice. Three connectors leave the PSU: a 24-pin cable with its 4-pin extension for the board, an 8-pin EPS cable for the processor and 6+2-pin PCI Express cables for graphics cards. Each slot’s plug shape is unique, which is why forcing a cable means it was the wrong one.

Why a PSU is sealed

A desktop PSU holds charge in its primary capacitors for several minutes after it is unplugged, at mains voltage behind the metal case. Only a technician who can measure and discharge those capacitors may open one. Replace a failed unit, do not open it; mains voltage inside the box can kill, and a sealed PSU of similar wattage from a reputable brand is one short order away.

USB Power Delivery is the matching idea for laptops and small devices: a cable and a charger that negotiate up to 240 W over a full-featured USB Type-C link, as the USB Implementers Forum describes. Its data side belongs to the next lesson, Ports, cables, displays and docking stations.

Three ways a UPS carries you through a cut

An uninterruptible power supply: A unit that keeps a device running on battery when the mains fail or wander. Its short name is UPS. The three common designs are standby, line-interactive and double conversion. keeps a device running when the mains fail, but how it does it differs by design. The three shapes a help desk meets are standby, line-interactive and double conversion, and the price, the gap on a cut and the kinds of problems each covers follow from the path mains power takes through the box.

A standby UPS passes the mains through to the devices while a small charger tops up a sealed lead-acid battery. When a brownout or a cut drops the mains below a threshold, a transfer switch moves the load to the inverter and the battery, which takes two to ten milliseconds. Desktops, routers and most phones tolerate the gap; a handful of industrial controllers restart. A standby UPS is the cheapest kind, and most 600 VA to 1,500 VA units sold for Indian homes and small offices are standby.

A line-interactive UPS: A UPS that adds an autotransformer to trim a low or high mains voltage back to the right range without touching the battery, saving the battery for a real cut. adds an autotransformer that trims a low or high mains voltage back to the right range, so a brownout: A drop in mains voltage below the specified range, often from heavy demand on the local supply, that can crash computers and damage motors over time. of 20 to 30 V no longer forces the battery to work. The battery is saved for a real cut, and the transfer time stays similar, two to five milliseconds. These sit under most office PCs and are a sensible step up from a basic unit where the mains voltage wanders.

A double conversion UPS: A UPS that feeds the inverter from a DC rail all the time, so a load sees no gap at all when the mains fail. Also called an online or on-line UPS. rectifies the mains into a DC rail and builds a clean mains wave from that rail every moment, so the inverter runs all the time and the battery hangs on the same rail. The device sees no gap at all when the mains fail, because nothing changes except where the DC rail is fed from. The cost is a lower efficiency (about 92 to 96 % against the near 99 % of a standby unit) and louder fans, which is why double conversion is the choice for servers, medical equipment and small racks, not home desks.

Interactive · stage by stage Standby, line-interactive and double conversion, in six beats Step through each type's path from the wall socket to the device, and the moment at which the battery takes over.
Three UPS types, from the socket to the computer, step 6 of 6. Showing Standby UPS, On a cut: 2-10 ms gap, Line-interactive UPS, An AVR trims voltage, Double conversion UPS, Battery always online. In focus: Battery always online.Standby UPShome and small officeOn a cut: 2-10 ms gapa switch moves to batteryLine-interactive UPShandles sags and surgesAn AVR trims voltagebattery kept for a cutDouble conversion UPSservers that must not blinkBattery always onlineno transfer time at all

The drawing shows the whole scene; its 6 steps are listed below.

Every step as text
  1. Standby UPS, normal power. A standby UPS passes the mains straight through to the devices while a small charger keeps the battery topped up. It is the cheapest kind, and the one most home and small office units sold in India belong to.
  2. Standby UPS, on a cut. When the mains drops, a transfer switch moves the load to the battery and the inverter in two to ten milliseconds. Desktops and routers tolerate the gap; a few sensitive devices restart.
  3. Line-interactive UPS, voltage. A line-interactive UPS adds an autotransformer that trims a low or high mains voltage back to the right range, so a brownout no longer draws from the battery. The battery is kept for a cut long enough to need it.
  4. Line-interactive UPS, on a cut. The transfer time is similar to a standby unit, about two to five milliseconds, but the battery stays fuller because it is not called on by every sag or surge. These sit under most office PCs.
  5. Double conversion, always on. A double conversion UPS feeds the inverter all the time: the mains runs through a rectifier to a direct-current rail, and the inverter builds a clean mains wave from that rail. The battery sits on the same rail.
  6. Double conversion UPS, on a cut. When the mains fails, the rectifier stops but the inverter keeps drawing from the battery, so the device sees no gap at all. The price is a lower efficiency and more fans, so it is used for servers and medical kit.

Checkpoint

Check: Standby, line-interactive and double conversion

  1. Question 1 of 2 A small clinic's ECG machine must not lose power for even a few milliseconds. Which UPS design do you quote?

    Choose one answer.

    Show the answer: Question 1 of 2

    Answer: Double conversion

    Only double conversion carries a load through a cut with no transfer time at all, so sensitive medical devices, servers and small racks are its home. The price is a lower efficiency and louder fans, which is why desks keep a cheaper design.

  2. Question 2 of 2 What does a line-interactive UPS do during a brownout that a standby UPS does not?

    Choose one answer.

    Show the answer: Question 2 of 2

    Answer: It trims the low mains voltage back to the right range without touching the battery

    A line-interactive UPS adds an autotransformer that corrects a wandering mains without calling on the battery. That matters where the mains sags often: the battery stays fuller for the real cuts, and lasts more years.

Sizing a UPS: VA, watts and power factor

Every UPS carries two limits on its box, and both have to hold for a load to fit. The first is watts, the actual work the inverter and the battery must do, counted as volts × amps for a direct-current load or the time-average of volts × amps for an alternating-current one. The second is volt-ampere: The apparent power a UPS inverter must build: the voltage across a load times the current it pulls, with no account of whether current and voltage are in step. Its symbol is VA. (volt-amperes), the apparent power the inverter must build; it is the voltage times the current the load pulls, with no account of whether that current is in step with the voltage.

The relationship between the two is the power factor: A number from 0 to 1 that says how much of the apparent power a load actually turns into work: watts equal volt-amperes times the power factor., a number from 0 to 1: watts equal volt-amperes times the power factor. A resistive load (an electric heater, an incandescent lamp) has a power factor near 1 and its watts and VA are almost the same. A load with a motor or an older power supply pulls current slightly ahead of or behind the voltage, so its power factor is 0.5 to 0.7 and its VA is well above its watts. A basic UPS feeding small single-phase devices is typically rated at a power factor of 0.6, which is why a label of 650 VA sits beside a label of 390 W: 650 × 0.6 = 390.

A small office load against two UPS options Python · ups_check/ups_check.py
# Size a UPS for a small office of two desktops, one Wi-Fi router, one fibre ONT and one monitor. Watts come from each
# device's label at normal use; VA follows from an apparent power factor the lesson derives (watts / power factor). Then
# the load is checked against two candidate UPS units, and a runtime estimate is drawn from the UPS's battery energy.
# All inputs are label values picked for a lesson, not a specific product.

devices = [
    # (name, watts under normal use)
    ("desktop A on a design job",   220),
    ("desktop B at the browser",     95),
    ("27-inch monitor",              28),
    ("Wi-Fi router",                  8),
    ("fibre ONT",                     6),
]
power_factor = 0.6   # a lesson value for small single-phase devices behind a basic UPS inverter

print(f"{'device':<26}{'watts':>8}")
for name, watts in devices:
    print(f"{name:<26}{watts:>8}")
load_w = sum(w for _, w in devices)
load_va = load_w / power_factor
print(f"{'total':<26}{load_w:>8}  <- the load in watts")
print(f"load in VA at PF={power_factor}: {load_va:.0f}  <- what the UPS sees as apparent power")
print()

# Two candidate UPS units: a basic home unit and an office-class one.
ups_units = [
    # (name, rated VA, rated W, battery nominal voltage, battery amp-hours)
    ("A: 650 VA / 390 W basic UPS",     650,  390, 12.0,  7.0),
    ("B: 1000 VA / 600 W office UPS",  1000,  600, 12.0,  9.0),
]
for name, rated_va, rated_w, v_batt, ah in ups_units:
    fits_va = load_va <= rated_va
    fits_w  = load_w  <= rated_w
    verdict = "fits" if fits_va and fits_w else "does NOT fit"
    battery_wh = v_batt * ah
    print(f"{name}")
    print(f"  VA limit {rated_va:>5}, load {load_va:>5.0f} VA -> {'ok' if fits_va else 'over by ' + f'{load_va - rated_va:.0f}'}")
    print(f"  W  limit {rated_w:>5}, load {load_w:>5} W  -> {'ok' if fits_w  else 'over by ' + f'{load_w  - rated_w:.0f}'}")
    print(f"  verdict: {verdict}")
    if fits_va and fits_w:
        # A rough runtime: battery energy divided by the load in watts, with an 85 % inverter efficiency.
        inverter = 0.85
        usable_wh = battery_wh * inverter
        minutes = (usable_wh / load_w) * 60
        print(f"  battery {battery_wh:.0f} Wh x 85% inverter = {usable_wh:.1f} Wh usable")
        print(f"  rough runtime at {load_w} W: {minutes:.1f} minutes (optimistic; see the next example)")
    print()

Output

device                       watts
desktop A on a design job      220
desktop B at the browser        95
27-inch monitor                 28
Wi-Fi router                     8
fibre ONT                        6
total                          357  <- the load in watts
load in VA at PF=0.6: 595  <- what the UPS sees as apparent power

A: 650 VA / 390 W basic UPS
  VA limit   650, load   595 VA -> ok
  W  limit   390, load   357 W  -> ok
  verdict: fits
  battery 84 Wh x 85% inverter = 71.4 Wh usable
  rough runtime at 357 W: 12.0 minutes (optimistic; see the next example)

B: 1000 VA / 600 W office UPS
  VA limit  1000, load   595 VA -> ok
  W  limit   600, load   357 W  -> ok
  verdict: fits
  battery 108 Wh x 85% inverter = 91.8 Wh usable
  rough runtime at 357 W: 15.4 minutes (optimistic; see the next example)

Recorded with Python 3.14.8 on macOS 26 arm64. To run it yourself: mise exec python@3.14.8 -- python3 ups_check.py

The office draws 357 W when desktop A is on a design job and desktop B is browsing: watts and VA, 357 and 595. Both the 650 VA / 390 W unit and the 1,000 VA / 600 W unit sit above each limit, so either fits on paper. The smaller unit’s VA headroom is 55 (595 against 650) and its watts headroom is 33 (357 against 390), so a tenth device of about 25 W is the last one it will accept. The MySmartCoPilot watts-to-amps calculator turns the same numbers in and out of volts, amps and watts for a quick second check.

Interactive · stage by stage Six steps from a device's label to a UPS that fits Follow the office load from each device's watts to the UPS that fits and a runtime a cut can use.
Sizing a UPS for the small office in six steps, step 6 of 6. Showing Read each device's watts, Sum: 357 W, VA = W / PF, Pick past both limits, Battery energy, Runtime, derated. In focus: Runtime, derated.Read each device's wattslabels and datasheetsSum: 357 Wthe work the UPS must doVA = W / PF357 / 0.6 = 595 VAPick past both limits650 VA / 390 WBattery energy12 V x 7 Ah = 84 WhRuntime, derated~5 min at 357 W

The drawing shows the whole scene; its 6 steps are listed below.

Every step as text
  1. Read each device's watts. Start from each device's label or datasheet: two desktops at 220 W and 95 W, one 27-inch monitor at 28 W, one Wi-Fi router at 8 W and one fibre ONT at 6 W. Pick the figure for normal, not peak, use.
  2. Add the watts. Add them up: 220 + 95 + 28 + 8 + 6 = 357 W. This is the real work the UPS must do while on battery, before any UPS loss. Add 20 % if the office may add a device without a new sum.
  3. Turn watts into VA. Divide watts by the power factor to get VA: at a power factor of 0.6 for a basic UPS, 357 W is 595 VA. The UPS reads VA directly because that is the apparent power its inverter must build.
  4. Pick a UPS past both limits. The chosen UPS must sit above the load on both: a 650 VA / 390 W unit fits (595 < 650 and 357 < 390), while a 650 VA / 325 W unit would trip on watts. Both numbers decide, not just the big one on the box.
  5. Battery energy. The battery's energy is its voltage times its amp-hours: a 12 V, 7 Ah battery holds 84 Wh of nameplate energy. A larger office UPS uses a 12 V, 9 Ah battery (108 Wh) or two 12 V batteries wired as 24 V.
  6. Honest runtime. Honest runtime is energy divided by watts, times 60, minus losses: 84 Wh x 0.85 inverter x 0.6 Peukert divided by 357 W gives about 7 minutes new, and 5 minutes after three years. Plan for a safe shutdown, not for all-day work.

Picking by VA alone

Wrong: “650 VA is more than 357 W, so it fits.” Right: 357 W of watts and 595 VA of apparent power are two different numbers that must each sit below the UPS’s two limits. A desktop at 320 W behind a 650 VA / 325 W unit fits on VA (533 against 650) and trips on watts (320 against 325) the first time a browser tab opens a video.

Both the examples’ numbers and the sizing flow pick the same unit from the same labels, so the arithmetic matches whether a learner reads the program or the figure. The office could in principle place the load on either unit; the 1,000 VA / 600 W box leaves more room for a desktop that the owner swaps for a workstation with a graphics card, which pulls another 200 W.

Key idea

Multiply volt-amperes by the power factor to get watts; a load fits a UPS only when its watts sit below the UPS’s W limit and its VA sit below the UPS’s VA limit, at the same time.

Checkpoint

Check: Sizing by VA, watts and power factor

  1. Question 1 of 2 A desktop draws 300 W at a power factor of 0.5. How many VA does the UPS see?

    Type a number.

    A hint

    Divide watts by the power factor to get VA.

    Show the answer: Question 1 of 2

    Answer: 600 VA (anything from 599 to 601 counts)

    Watts equal VA times the power factor, so VA equal watts divided by the power factor: 300 ÷ 0.5 = 600 VA. The same desktop at a power factor of 0.9 would show the UPS 333 VA for the same 300 W.

  2. Question 2 of 2 A 650 VA / 325 W UPS is proposed for a 320 W desktop whose power factor is 0.6 (so 533 VA). Does the load fit?

    Choose one answer.

    Show the answer: Question 2 of 2

    Answer: No, it fits VA but trips on watts

    Both the VA and the W limits of a UPS must sit above the load, with headroom for the next device the user may plug in. A 5 W margin is not headroom; the right choice is a 650 VA / 390 W unit (65 W of margin) or larger.

The honest runtime: battery age, inverter loss and the Peukert effect

Nameplate runtime is the UPS’s battery energy divided by the load. The battery energy is its voltage times its amp-hour rating: a sealed 12 V, 7 Ah battery inside a 650 VA unit holds 84 watt-hours of nameplate energy, and divided by a 357 W load that gives 14.1 minutes of raw autonomy. The real figure is well below that for three reasons the help desk cannot wish away.

The first is inverter loss. The inverter and the transfer stage of a basic UPS give back about 85 % of the battery’s energy as alternating current; the other 15 % becomes heat in the box. The second is battery age. A sealed lead-acid battery kept at Indian room temperatures loses about 20 % of its usable charge after three years and about 40 % after five, even when it is never used, because the internal plates sulfate as the chemistry settles. The third is the Peukert effect: a lead-acid battery delivers less of its rated capacity at a high discharge rate than at a low one, with a Peukert exponent of about 1.2 to 1.3 for a typical unit, which costs another 40 % at the kinds of currents a desktop load pulls.

From the 14-minute nameplate to the 4-minute reality Python · runtime_derate/runtime_derate.py
# The rough runtime from ups_check.py divided a UPS battery's nameplate energy by the load. Three things pull the real
# runtime below that: the inverter loses some energy as heat; a battery stops holding its full charge after a few years;
# and a lead-acid battery gives less energy when it is drained quickly, the Peukert effect. The program walks each one
# across the load the previous example found, and across a lighter load for an ONT and a router alone.

def runtime_min(battery_wh, load_w, inverter=0.85, age=1.0, peukert=1.0):
    """Minutes a UPS lasts: usable energy over the load. Each factor is between 0 and 1 (except peukert, see note)."""
    # Peukert: at a high discharge rate, a lead-acid battery delivers less of its labelled energy. For a 7 Ah battery
    # a load that empties it in under 15 minutes typically gives about 60 % of the nameplate at a Peukert exponent of
    # about 1.3; a slower discharge gives about 90 %. The factor is picked for the lesson, not fitted to one model.
    usable_wh = battery_wh * inverter * age * peukert
    return (usable_wh / load_w) * 60

# The small office of ups_check.py: 357 W behind a basic UPS with a 12 V / 7 Ah battery (84 Wh nameplate).
battery_wh = 12 * 7
load_desk = 357
load_light = 14   # the Wi-Fi router (8 W) and the fibre ONT (6 W), the two devices that keep the office online

print(f"{'case':<34}{'inv':>6}{'age':>6}{'Pk':>6}{'minutes':>10}")
cases = [
    ("nameplate: Wh over watts",         1.00, 1.00, 1.00),
    ("+ 85 % inverter efficiency",       0.85, 1.00, 1.00),
    ("+ 3-year battery, 80 % left",      0.85, 0.80, 1.00),
    ("+ Peukert at a fast discharge",    0.85, 0.80, 0.60),
    ("5-year battery (60 % left)",       0.85, 0.60, 0.60),
]
for name, inv, age, pk in cases:
    minutes = runtime_min(battery_wh, load_desk, inv, age, pk)
    print(f"{name:<34}{inv:>6.2f}{age:>6.2f}{pk:>6.2f}{minutes:>8.1f} min")

print()
print(f"the same five cases, but with the two desktops and the monitor switched off, keeping only the router and ONT ({load_light} W):")
for name, inv, age, pk in cases:
    minutes = runtime_min(battery_wh, load_light, inv, age, pk)
    print(f"{name:<34}{inv:>6.2f}{age:>6.2f}{pk:>6.2f}{minutes:>8.1f} min")

print()
print("so a 3-year-old 650 VA UPS at 357 W gives only about 5 minutes, barely enough to save work; the same UPS")
print("keeps a router and ONT online for about 2 hours. A plan that leaves the office with the network is often more")
print("useful than one that keeps the desktops awake for 4 or 5 minutes extra.")

Output

case                                 inv   age    Pk   minutes
nameplate: Wh over watts            1.00  1.00  1.00    14.1 min
+ 85 % inverter efficiency          0.85  1.00  1.00    12.0 min
+ 3-year battery, 80 % left         0.85  0.80  1.00     9.6 min
+ Peukert at a fast discharge       0.85  0.80  0.60     5.8 min
5-year battery (60 % left)          0.85  0.60  0.60     4.3 min

the same five cases, but with the two desktops and the monitor switched off, keeping only the router and ONT (14 W):
nameplate: Wh over watts            1.00  1.00  1.00   360.0 min
+ 85 % inverter efficiency          0.85  1.00  1.00   306.0 min
+ 3-year battery, 80 % left         0.85  0.80  1.00   244.8 min
+ Peukert at a fast discharge       0.85  0.80  0.60   146.9 min
5-year battery (60 % left)          0.85  0.60  0.60   110.2 min

so a 3-year-old 650 VA UPS at 357 W gives only about 5 minutes, barely enough to save work; the same UPS
keeps a router and ONT online for about 2 hours. A plan that leaves the office with the network is often more
useful than one that keeps the desktops awake for 4 or 5 minutes extra.

Recorded with Python 3.14.8 on macOS 26 arm64. To run it yourself: mise exec python@3.14.8 -- python3 runtime_derate.py

The chain is honest and short: 14.1 min on the nameplate becomes 12.0 min after the inverter, 9.6 min after a 3-year-old battery, and 5.8 min once the Peukert loss is counted at that discharge rate. A 5-year-old unit on the same load gives 4.3 minutes. The second table on the run shows what happens when the two desktops and the monitor are shut down and only the Wi-Fi router and the ONT stay on: 14 W instead of 357 W turns the same UPS into a 2-hour network keeper, which is often more useful on a 90-minute cut than keeping the desktops awake for four extra minutes. The battery life calculator does the same chain for any battery, load and derating.

Checkpoint

Check: Honest runtime after the three losses

  1. Question 1 of 2 A 3-year-old 650 VA UPS has an 84 Wh battery, an 85 % inverter and a Peukert factor of 0.6 at this discharge. How many minutes does it last at 357 W?

    Type a number.

    A hint

    Multiply 84 by 0.85, by 0.8 (age) and by 0.6, divide by 357 and multiply by 60.

    Show the answer: Question 1 of 2

    Answer: 5.8 minutes (anything from 5.5 to 6.1 counts)

    Usable energy is 84 × 0.85 × 0.8 × 0.6 = 34.3 Wh; dividing by 357 W and multiplying by 60 gives 5.8 minutes, the same figure runtime_derate.py prints. Five minutes is enough to save work; a five-year-old unit at 60 % capacity drops it to 4.3 minutes, the opening story's time.

  2. Question 2 of 2 Switching the two desktops and the monitor off leaves only the Wi-Fi router (8 W) and the ONT (6 W) on the same 3-year-old UPS. About how many minutes does it keep the network up?

    Type a number.

    Show the answer: Question 2 of 2

    Answer: 147 minutes (anything from 137 to 157 counts)

    The load is 14 W instead of 357 W. Usable energy is 84 × 0.85 × 0.8 × 0.6 = 34.3 Wh; 34.3 ÷ 14 × 60 is about 147 minutes, which runtime_derate.py prints as 146.9. On a 90-minute cut, a plan that drops the desktops and keeps the network often beats one that keeps the desktops awake for an extra four minutes.

Surge protector or UPS, and when either is enough

A surge protector: A strip or brick that clamps mains voltage spikes with a varistor, absorbing joules until the rating is spent. It has no battery and does not help a cut. is a strip or a brick that clamps mains voltage spikes through a metal-oxide varistor, which absorbs the spike as heat and dies a little each time. The strip’s specification is the joules it is rated to absorb (300 to 2,000 for consumer models) and whether an indicator light reports when the varistor has used its budget up. A spike that costs the varistor 200 J of its 600 J rating leaves 400 J for the next ones, and once the rating is spent the strip still passes mains to the socket with no protection at all: the light is the only sign.

A UPS carries the surge protector’s job in its input stage and adds the battery. On a brownout or a cut it switches the load to the inverter; on a spike it clamps the spike before it reaches the output. So the question is never whether to pick a surge protector or a UPS; it is whether a cut matters here as well as a spike. A printer, a scanner and most set-top boxes shrug off a 5-minute cut and come back on their own, so a surge protector is enough; a desktop, a server and a Wi-Fi router under VoIP need a UPS as well because losing power mid-write risks a corrupted file system or a dropped call.

In India the mains voltage sits at 220 to 240 V and nominally 50 Hz, with cuts and brownouts common enough that a UPS is a desk accessory and not a server-room feature. Size a desk UPS for a safe shutdown of three to five minutes rather than all-day work; for all-day work the budget is an inverter and a battery bank, not a UPS, and the question moves out of this lesson into generator and electrical scope.

Where the mains sits here

Indian single-phase mains is specified at 230 V ± 10 % and 50 Hz ± 3 % by the Central Electricity Authority, which maps to 207 to 253 V and 48.5 to 51.5 Hz. A line-interactive UPS keeps the output within tighter bounds without touching the battery; a double conversion UPS gives a clean output from the first millisecond.

Laptops, phones and the growing number of small UPS units with lithium-ion packs share one failure mode no help desk should ever work through: a lithium-ion cell: A rechargeable cell used in laptops, phones and newer UPS units. A puffed or distorted cell is a safety stop-work sign and goes to an authorised recycler. that has puffed up and pressed the case open. A swollen cell is a cell whose electrolyte has broken down and released gas, usually from heat, overcharging, a manufacturing defect or old age. Pressing it, puncturing it or trying to force it back into shape risks a fire that burns at over 1,000 degrees and that water will not put out.

Battery health is a quieter signal most of the time. macOS reports the Maximum Capacity of a laptop’s battery under Battery → Battery Health (85 % of nameplate at two years is a usual figure); Windows writes a full report through powercfg /batteryreport (Microsoft’s own documentation describes the HTML file it emits, which lists design capacity against full-charge capacity). When Full Charge Capacity drops below 80 % of the design value, the user’s day shortens, the fan runs harder and a battery service is on order.

A puffed cell has three warning signs the user usually notices first: the trackpad or the keyboard rises a little, the laptop no longer sits flat on the desk, or the back cover begins to separate from the frame. One is enough to stop work. A phone’s screen can lift at its edges for the same reason; an older power bank’s case can split along its seam. The thickness of the swelling says nothing about how close the cell is to failing, so the rule is the same for a gentle bulge and a dramatic one: do not use the device until it is in a recycler’s hands. Replacing the battery alone restores the device for the user in most cases; the laptop goes to its maker’s service centre or an authorised repair partner, with the swollen pack isolated for the trip.

Interactive · stage by stage Four steps that keep the user and the office safe Follow a short, strict stop-work routine when a laptop, phone or UPS battery has puffed up or distorted the case.
Swollen battery: four steps that keep the user safe, step 5 of 5. Showing Stop the user, Power off and unplug, Isolate the device, Hand to a recycler. In focus: Hand to a recycler.never prise it openStop the userno charging, no pressingPower off and unplughold the power buttonIsolate the devicemetal tin, away from paperHand to a recyclera producer's take-back

The drawing shows the whole scene; its 5 steps are listed below.

Every step as text
  1. Stop the user. A puffed battery is a stop-work sign, not a bug to work around. Ask the user to stop charging it, stop pressing on the case, and stop using the device, even if work is unsaved: the saving is not worth the risk.
  2. Power off and unplug. Shut the device down. If it will not shut down, hold the power button until it does. Unplug every cable and remove any removable battery with care, straight out and without flexing the cell.
  3. Isolate the device. Put the device in a non-flammable container such as a metal tin or a ceramic plate, away from paper, cloth and anything that catches fire easily. Leave it where you can see it until a recycler takes it on.
  4. Never prise it open. Do not try to open the device or the pack to get the battery out. A puncture or a short can start a fire that water will not put out. Only a trained technician with the right tools may handle the cell.
  5. Hand to an authorised recycler. Lithium-ion cells must go to a recycler registered with the state pollution control board under the Battery Waste Management Rules, 2022. Many producers run a take-back for their own batteries; ask the user's workplace which route they use.

Disposal is legal, not optional

The Battery Waste Management Rules, 2022, administered by the Central Pollution Control Board, require every battery to be routed to a recycler registered on the state pollution control board’s list. Most phone and laptop makers run a producer take-back for their own batteries through the producer’s extended responsibility programme; the office’s facilities team usually knows which route it uses. A used lithium-ion cell is never thrown in with ordinary waste.

Checkpoint

Check: Swollen cells and legal disposal

  1. Question 1 of 2 A user shows you a laptop whose palm rest has started to bulge upward. What is the first thing you do?

    Choose one answer.

    Show the answer: Question 1 of 2

    Answer: Ask the user to stop using the laptop, then shut it down and unplug it

    A swollen battery is handled as a safety issue, not a hardware fault. The procedure is stop, shut down, isolate in a non-flammable container, and route to an authorised recycler; the device never comes back into service with the same cell.

  2. Question 2 of 2 Who may take a dead or swollen laptop battery for disposal in India?

    Choose one answer.

    Show the answer: Question 2 of 2

    Answer: A recycler registered under the Battery Waste Management Rules, 2022

    The Battery Waste Management Rules, 2022, cover every battery sold in India. Most laptop and phone producers run a producer take-back for their own batteries under the producer's extended responsibility; a state pollution control board's list names every other registered recycler.

Practise: a load, a UPS and whether the two fit

Write the function the help desk reaches for before buying a UPS. It takes a list of devices, each with its watts, and a UPS’s VA and W limits, and reports whether the load fits on both. Keep both flags visible, because a load over on VA alone is a common pattern a single boolean would hide.

Exercise · Easy · Python

Check a load against a UPS's VA and W limits

Write ups_load_check(devices, va, watts, power_factor=0.6) so that a help desk can check whether a UPS is sized for a load before placing an order.

  • devices is an iterable of (name, watts) pairs, each watt figure a non-negative number from a device's label.
  • va and watts are the UPS's labelled VA and W limits.
  • power_factor is the apparent power factor the UPS sees for this kind of load (0.6 is a lesson default; 0.9 is typical for a modern desktop with an active PFC supply).

Return a dict:

{
    "load_w": <int>,     # sum of the devices' watts, rounded to the nearest whole watt
    "load_va": <int>,    # load_w divided by the power factor, rounded to the nearest VA
    "fits_w": <bool>,    # load_w <= watts
    "fits_va": <bool>,   # load_va <= va
    "fits": <bool>,      # both limits hold
}

Raise ValueError when a device's watts are negative, or when power_factor is not between 0 (open) and 1 (closed). Empty inputs are a valid question: an empty UPS fits every empty load.

Starter code · ups_load_check.py

def ups_load_check(devices, va, watts, power_factor=0.6):
    """Return load watts and VA, and whether a UPS of (va, watts) fits them at the given power factor."""
    return {"load_w": 0, "load_va": 0, "fits_w": False, "fits_va": False, "fits": False}
The sample tests · test_ups_load_check.py
from ups_load_check import ups_load_check


def test_empty_load_fits_anything():
    """an empty office load is a passing check against any UPS"""
    result = ups_load_check([], va=400, watts=240)
    assert result == {"load_w": 0, "load_va": 0, "fits_w": True, "fits_va": True, "fits": True}


def test_small_office_fits_the_basic_ups():
    """357 W of office kit at power factor 0.6 fits a 650 VA / 390 W unit (595 < 650, 357 < 390)"""
    load = [("desktop A", 220), ("desktop B", 95), ("monitor", 28), ("router", 8), ("ONT", 6)]
    result = ups_load_check(load, va=650, watts=390)
    assert result["load_w"] == 357
    assert result["load_va"] == 595
    assert result["fits_w"] is True
    assert result["fits_va"] is True
    assert result["fits"] is True


def test_over_only_watts():
    """a load inside the VA box but over on watts fails as a whole"""
    load = [("space heater", 1500)]
    result = ups_load_check(load, va=3000, watts=1000, power_factor=0.9)
    assert result["load_w"] == 1500
    assert result["load_va"] == 1667
    assert result["fits_w"] is False
    assert result["fits_va"] is True
    assert result["fits"] is False


def test_over_only_va():
    """a load inside watts but over on VA fails as a whole (low power factor)"""
    load = [("laser printer idle", 25), ("old pump motor", 150)]
    result = ups_load_check(load, va=200, watts=250, power_factor=0.5)
    assert result["load_w"] == 175
    assert result["load_va"] == 350
    assert result["fits_w"] is True
    assert result["fits_va"] is False
    assert result["fits"] is False


def test_power_factor_defaults_to_zero_point_six():
    """the default power factor is 0.6, so 300 W becomes 500 VA"""
    assert ups_load_check([("one", 300)], va=1000, watts=1000)["load_va"] == 500


def test_rounds_to_the_nearest_whole_number():
    """non-integer watts round to the nearest VA, not a floor"""
    assert ups_load_check([("fan", 11.5)], va=100, watts=100, power_factor=0.9)["load_va"] == 13


def test_rejects_a_negative_watt_figure():
    """a device cannot draw negative power"""
    try:
        ups_load_check([("mystery", -10)], va=100, watts=100)
    except ValueError:
        return
    raise AssertionError("ups_load_check with -10 W should raise ValueError")


def test_rejects_an_impossible_power_factor():
    """a power factor must sit in (0, 1]"""
    for bad in (0, -0.5, 1.1):
        try:
            ups_load_check([("one", 100)], va=200, watts=200, power_factor=bad)
        except ValueError:
            continue
        raise AssertionError(f"ups_load_check with power_factor={bad} should raise ValueError")
A hint

Add up the watts first and refuse any negative figure as you walk the list. Then compute VA as watts divided by the power factor, round both to the nearest whole number, and compare each one with its limit. Keep the two "fits" flags separate until the end: a UPS over on VA alone is a common pattern, and the dict makes that visible.

The sample tests run on this device, in your browser (Pyodide): nothing is sent to mysmartcopilot.com. The first run downloads Python (about 13.5 MB), which is kept for the next runs. A check in your browser is feedback for you, not proof that the code is right for every input.

Practice that adapts to you

Practise this lesson

12 questions about 6 ideas of this lesson. Each answer is explained at once, and what you get right is kept in this browser.

  1. Question 1 of 12 Which three low voltages come out of a desktop PSU?

    Choose one answer.

    Show the answer: Question 1 of 12

    Answer: +12 V, +5 V and +3.3 V

    Modern ATX supplies ship +12 V as the heavy rail and keep +5 V and +3.3 V for the lighter work. power_rails.py prints the amps each one supplies, with the sum of their maxima well above the label total: the PSU can give every rail its share, but not every rail at once.

  2. Question 2 of 12 Why is a desktop PSU replaced rather than opened for repair?

    Choose one answer.

    Show the answer: Question 2 of 12

    Answer: Its primary capacitors hold mains voltage for several minutes after it is unplugged

    Mains voltage behind a metal case takes longer to bleed off than most people expect, which is why a dead PSU is replaced with a sealed unit of similar wattage from a reputable brand. The failed one goes to electronic waste, not to the bench.

  3. Question 3 of 12 A 500 W PSU with an 80 Plus Bronze rating is 82 % efficient at 50 % load (250 W out). How many watts does it draw from the wall at that load, to the nearest watt?

    Type a number.

    Show the answer: Question 3 of 12

    Answer: 305 W (anything from 303 to 307 counts)

    Input watts equal output watts divided by efficiency: 250 ÷ 0.82 = 305 W from the socket, so 55 W is heat. Higher 80 Plus bands narrow the loss: Platinum at the same 50 % load gives 273 W in and 23 W of heat.

  4. Question 4 of 12 A small radiology clinic has a workstation, a report printer and an ultrasound machine, and the mains wander by 20 to 30 V several times a day. Which UPS design do you quote, and why?

    Choose one answer.

    A hint

    Decide separately for the voltage wander and for the no-blink requirement, then pick one unit that covers both.

    Show the answer: Question 4 of 12

    Answer: Double conversion, because the ultrasound machine cannot tolerate a transfer time

    The clinic's two problems are the wander (which both line-interactive and double conversion handle) and the no-blink need for the ultrasound (which only double conversion handles). A double conversion UPS covers both at a lower efficiency and higher cost, which is the right trade here.

  5. Question 5 of 12 A modern desktop with active PFC draws 600 W at a power factor of 0.9. How many VA does the UPS see?

    Type a number.

    Show the answer: Question 5 of 12

    Answer: 667 VA (anything from 666 to 668 counts)

    Watts equal VA times the power factor, so VA equal 600 ÷ 0.9 = 667. The same desktop on a UPS rated at a power factor of 0.6 would show 1,000 VA on paper; always check the UPS's own PF before dividing.

  6. Question 6 of 12 The small office of the lesson's example sits at 357 W and 595 VA on a 650 VA / 390 W UPS. The user wants to plug in a 25 W desk fan. Does the unit still fit?

    Choose one answer.

    Show the answer: Question 6 of 12

    Answer: Yes, 382 W and 637 VA both still sit below the limits

    Each extra device adds its watts to the W total and about watts ÷ 0.6 to the VA total. A 25 W fan adds about 42 VA, which the unit absorbs. The next addition is the one to watch: watts headroom is already down to 8 W.

  7. Question 7 of 12 What nameplate runtime does an 84 Wh battery give at a load of 357 W, before any derating?

    Type a number.

    A hint

    Divide the battery energy by the load in watts, then multiply by 60 to get minutes.

    Show the answer: Question 7 of 12

    Answer: 14.1 minutes (anything from 13.8 to 14.4 counts)

    84 ÷ 357 = 0.235 hour, which is 14.1 minutes. This is the number the UPS sticker would use; the three losses (inverter, battery age, Peukert) between the sticker and reality cost about 60 % of it.

  8. Question 8 of 12 Why does the Peukert effect make a lead-acid UPS last less time at a desktop load than its nameplate says?

    Choose one answer.

    Show the answer: Question 8 of 12

    Answer: A high discharge rate makes less of the battery's chemistry reachable before the voltage drops too low

    Lead-acid chemistry needs the electrolyte to carry ions between the plates. At a high current the electrolyte near the plates runs out faster than the rest can mix across, so the terminal voltage drops before every charge is converted. The effect is the Peukert exponent, around 1.2 to 1.3 for a typical UPS battery.

  9. Question 9 of 12 A desk has a laser printer, a Wi-Fi router, a desktop that saves work locally and a laptop charger. The office has frequent short cuts. Which units go behind a UPS and which behind a surge protector?

    Choose one answer.

    Show the answer: Question 9 of 12

    Answer: Desktop and router on the UPS; laser printer and laptop charger on a surge protector

    A UPS protects what loses data or voice in a cut (desktops, routers under VoIP, servers); a surge protector is enough for what shrugs off a cut and only needs the spike filter (printers, chargers, set-top boxes). A laser printer in particular belongs on its own circuit, never behind a UPS; its fuser spikes trip almost every unit.

  10. Question 10 of 12 What happens to a consumer-grade surge protector after it has absorbed several spikes?

    Choose one answer.

    Show the answer: Question 10 of 12

    Answer: Its varistor wears out silently, so the strip passes mains without protection

    The varistor dies a little each time it clamps a spike. A good strip has a protection-active light that goes out when the rating is used up; without that light, a strip that has been in service for years may still pass mains but offer no real protection, which is why the light matters as much as the joule rating.

  11. Question 11 of 12 A two-year-old laptop battery typically retains about what fraction of its design capacity, as a percentage?

    Type a number.

    Show the answer: Question 11 of 12

    Answer: 85 % (anything from 80 to 90 counts)

    Most laptop batteries report about 85 % of design capacity at two years of normal use; below 80 % the user's day becomes noticeably shorter and a battery service is on the order sheet. macOS shows this as Maximum Capacity under Battery Health; Windows writes a full report through powercfg /batteryreport.

  12. Question 12 of 12 A user hands you a swollen laptop battery after you have shut the laptop down. What is the correct next route?

    Choose one answer.

    Show the answer: Question 12 of 12

    Answer: Isolate the device, then arrange a producer take-back or a recycler on the state board's list

    The two legal routes under the 2022 rules are the producer's take-back (at no cost for the device's own battery) and a recycler registered with the state pollution control board. The user's workplace facilities team usually knows which route it uses; either is acceptable, and ordinary waste is not.

Interview questions

Warm-up (fresher): a user says a 1,000 VA UPS fits their 600 W PC because 1,000 is more than 600. What do you check before you agree?

The two numbers are measured in different units and both have to hold. Check the UPS’s watts rating as well as its VA rating; most 1,000 VA units are 600 W, so a 600 W desktop at a power factor of 0.9 (a modern PSU with active PFC) draws 600 W and about 667 VA, which fits both. The same desktop at a power factor of 0.6 (an older or very basic unit) would draw 1,000 VA for the same 600 W, which still fits VA, but any extra load would trip the UPS. Also check that 600 W is the real draw and not the PSU’s label: a 600 W PSU usually sees 150 to 250 W in office work, so the real load is well below the UPS’s W limit and the headroom goes to runtime instead.

Two harder cases follow. Decide a first step on each from what you have read, then open the question to see how far your plan matches the model:

Model answers open with any pass: ₹79 for 1 week ($2.99), one payment that never renews.

  1. Fresher to mid

    A small office complains that its 3-year-old 650 VA / 390 W UPS, which they bought because the catalogue said "backs up a desktop for 15 minutes", only gives them about 4 minutes when the lights go. Walk through the diagnosis and the fix, and say what you would quote now.

    Model answer, Pro. Model answers open with any pass; prices are in the notice on this page. First step and follow-ups

  2. Mid to senior

    An office in a town that loses mains for 60 to 90 minutes several times a week wants its two desktops, monitor, fibre ONT and Wi-Fi router to "stay up through every cut" on a budget. The owner has already bought a 1,000 VA line-interactive UPS. What do you plan, and what do you tell the owner?

    Model answer, Pro. First step and follow-ups

Flashcards · 7 cards

Recall it, then check

Say the answer to yourself before you look: recalling it is what makes it stick.

  1. Why is a failed desktop power supply replaced rather than opened?

    Its primary capacitors hold mains voltage for several minutes after it is unplugged. The unit turns mains into +12 V, +5 V and +3.3 V rails and stays sealed.

  2. How do standby, line-interactive and double conversion UPS designs differ?

    Standby is the cheapest. Line-interactive trims a brownout back into range without touching the battery. Double conversion feeds the load from its inverter all the time, so the load sees no gap when the mains fail.

  3. When does a load fit a UPS?

    Only when its watts are under the UPS's watt limit and its volt-amperes under its VA limit, both at once. Watts equal volt-amperes times the power factor.

  4. A user says a 1,000 VA UPS fits a 600 W PC because 1,000 is more than 600. What do you check?

    The UPS's watt rating as well: most 1,000 VA units are 600 W. At a power factor of 0.9 the PC draws about 667 VA and fits both limits; at 0.6 it draws the full 1,000 VA, with no room for any extra load. Also check the real draw, not the PSU label.

  5. What cuts a UPS's runtime below the battery energy divided by the load?

    About 15 % lost in the inverter, about 20 % for a 3-year-old battery and about 40 % for the Peukert effect, so a 650 VA unit at 357 W lasts under 6 minutes, not 14.

  6. What does a surge protector do, and what can it not do?

    It clamps mains spikes with a varistor until its joule rating is used up. It has no battery, so it does nothing for a power cut.

  7. What do you do with a swollen lithium-ion battery?

    Stop work: shut the device down, isolate it in a non-flammable container, never prise it open, and send it to a registered recycler.

Key takeaways

  • A desktop PSU splits mains into +12 V, +5 V and +3.3 V rails and stays sealed; its primary capacitors hold mains voltage for several minutes after it is unplugged, so a failed unit is replaced, not opened.
  • Standby, line-interactive and double conversion UPS designs trade cost for a shorter transfer time and cleaner output: standby is the cheapest; line-interactive handles brownouts without the battery; double conversion gives no gap at all.
  • A UPS has two limits, VA and watts, and a load fits only when its watts and its VA sit below both at the same time; watts equal VA times the power factor the inverter sees.
  • Honest UPS runtime is the battery’s energy divided by the load, then cut by about 15 % for the inverter, about 20 % for a 3-year-old battery and about 40 % for the Peukert effect: a 650 VA unit at 357 W lasts 5 minutes, not 14.
  • A swollen lithium-ion battery is a stop-work sign: shut the device down, isolate it in a non-flammable container, never prise it open, and route it to a recycler registered under the Battery Waste Management Rules, 2022.

Terms in this lesson

brownout
A drop in mains voltage below the specified range, often from heavy demand on the local supply, that can crash computers and damage motors over time.
double conversion UPS
A UPS that feeds the inverter from a DC rail all the time, so a load sees no gap at all when the mains fail. Also called an online or on-line UPS.
line-interactive UPS
A UPS that adds an autotransformer to trim a low or high mains voltage back to the right range without touching the battery, saving the battery for a real cut.
lithium-ion cell
A rechargeable cell used in laptops, phones and newer UPS units. A puffed or distorted cell is a safety stop-work sign and goes to an authorised recycler.
power factor
A number from 0 to 1 that says how much of the apparent power a load actually turns into work: watts equal volt-amperes times the power factor.
power supply unit
The box inside a desktop computer that turns the mains voltage into +12 V, +5 V and +3.3 V rails for the board, drives and cards. Its short name is PSU.
surge protector
A strip or brick that clamps mains voltage spikes with a varistor, absorbing joules until the rating is spent. It has no battery and does not help a cut.
uninterruptible power supply
A unit that keeps a device running on battery when the mains fail or wander. Its short name is UPS. The three common designs are standby, line-interactive and double conversion.
USB Power Delivery
A specification by the USB Implementers Forum for sending up to 240 W over a full-featured USB Type-C link, negotiated between the charger and the device. Its short name is USB PD.
volt-ampere
The apparent power a UPS inverter must build: the voltage across a load times the current it pulls, with no account of whether current and voltage are in step. Its symbol is VA.

References

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