Voltage Divider Calculator
Divider output, the resistors for a target voltage, and bridges — with the load included.
Standard values for R2
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Best standard pairs
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How it was calculated
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How it was calculated
How it was calculated
How it was calculated
About the Voltage Divider Calculator
A voltage divider is two resistors in series: the output, taken across R2, is Vin × R2 / (R1 + R2). Enter the input and both resistors to get the output, or enter the output you need and solve for R1 or R2. The calculator then rounds to the standard values you stock (E6 to E192), lists the best standard pairs with their exact output and error, and shows the divider current, the power in each resistor and the output (Thevenin) resistance.
Add a load resistance — the input of an ADC, a meter or the next stage — and every figure includes it, including how far the load pulls the output down. Separate modes cover the current divider, the Wheatstone bridge (balance point and output voltage) and strain-gauge bridges in quarter-, half- and full-bridge form, from strain to millivolts and back.
How to use it
- Choose a mode. For a voltage divider, choose what to solve for: the output, R2 or R1.
- Enter the input voltage and the known values. Resistors take prefixes and codes — 10k, 4k7, 2M2 — or use the unit list.
- Optionally enter the load resistance connected to the output, and choose the E-series you want the result rounded to.
- Read the result, the best standard pairs and the working. For bridges, enter the excitation voltage and the four arms, or pick a strain-gauge configuration with its gauge factor.
Examples
Vin 5 V, R1 10k, R2 10k
Vout 2.5 V, 250 µA, output resistance 5 kΩ
Same divider, 10 kΩ load
Vout 1.667 V — the load pulls it down by a third
Solve R2 with R1 = 10k
R2 = 19.41 kΩ; E24 20k gives 3.333 V (+1.0%); best E24 pair 4.7k / 9.1k gives 3.297 V (−0.09%)
Solve R2 with R1 = 10k and RL 100k
R2 = 7.692 kΩ (7.143 kΩ in parallel with the load)
10 mA into 1 kΩ ‖ 2 kΩ
6.667 mA and 3.333 mA
GF 2.0, 1000 µε, 10 V excitation
4.995 mV (0.4995 mV/V), 0.1% below the linear 5 mV
Formulas
- Output: Vout = Vin × R2′ / (R1 + R2′), where R2′ = R2 ‖ RL = R2·RL / (R2 + RL) with a load RL (R2′ = R2 without one).
- Solving: R2′ = R1 × Vout / (Vin − Vout), then R2 = 1 / (1/R2′ − 1/RL) with a load; R1 = R2′ × (Vin − Vout) / Vout.
- Thevenin equivalent (what the output looks like to whatever you connect): Vth = Vin × R2 / (R1 + R2) and Rth = R1 ‖ R2. The lower Rth is compared with the load, the less the load changes the output.
- Current divider: Ik = I × (1/Rk) / Σ(1/Rj); for two resistors I1 = I × R2 / (R1 + R2).
Choosing the resistor values
The ratio sets the output; the size of the resistors sets the current and the output resistance. Small values waste current (and power in the resistors); large values make the output easily pulled down by the load and more sensitive to noise. A common rule is to make the divider current at least ten times the load current, or Rth well below the input resistance of whatever reads it — an ADC datasheet usually gives a maximum source impedance. The best-pairs table keeps one resistor within a factor of about three of the value you entered, so the current stays similar.
Wheatstone bridge
Two dividers side by side, fed from the same excitation voltage Vex: R1 (top left) and R2 (bottom left), R4 (top right) and R3 (bottom right). The output between the two midpoints is Vout = Vex × (R3/(R3 + R4) − R2/(R1 + R2)), and it is zero — the bridge is balanced — when R1 × R3 = R2 × R4. Wheatstone published the method in 1843; it is still how strain gauges, RTDs and load cells turn tiny resistance changes into a measurable voltage.
Strain-gauge bridges
With gauge factor GF and strain ε (x = GF × ε), the output per volt of excitation Vr = Vout / Vex is:
- Quarter bridge, one active gauge: Vr = (x/4) / (1 + x/2)
- Half bridge, bending (+ε and −ε gauges in adjacent arms): Vr = x/2
- Half bridge, axial with a Poisson gauge (+ε and −ν·ε): Vr = (1 + ν)·x / (4 + 2(1 − ν)·x)
- Full bridge, bending (four active gauges): Vr = x
- Full bridge, bending with Poisson gauges: Vr = (1 + ν)·x / 2
- Full bridge, axial with Poisson gauges: Vr = (1 + ν)·x / (2 + (1 − ν)·x)
The quarter and axial bridges are slightly nonlinear: the calculator shows the exact output, the linear approximation and the difference (about 0.1% per 1000 µε for a quarter bridge with GF = 2). Metal-foil gauges have a gauge factor of about 2; take the exact value from the gauge package. Poisson’s ratio ν is about 0.3 for steel and 0.33 for aluminium. Going from a reading back to strain, an output the bridge cannot produce, or one that would mean more than 100,000 µε (10%), is reported as a likely typo rather than turned into a strain.
Sources
- IEC 60063:2015, Preferred number series for resistors and capacitors (E-series)
- Vishay Micro-Measurements Tech Note TN-507-1, Errors Due to Wheatstone Bridge Nonlinearity
- NI, Measuring Strain with Strain Gages (quarter-, half- and full-bridge configurations; about 0.5 mV/V at 1000 µε for a quarter bridge and 2.0 mV/V for a full bridge; gauge factor about 2 for metal gauges)
- Wheatstone, C. (1843), “An account of several new instruments and processes for determining the constants of a voltaic circuit”, Phil. Trans. R. Soc. 133: 303–327
Limitations
- Resistors are taken at their nominal value: a ±1% resistor pair can move the output by up to about ±1%. The best-pairs errors are from nominal values only.
- The load is treated as a resistance. Inputs that draw a pulsed or changing current (such as a sampling ADC) may need a buffer or a capacitor across R2.
- A divider is not a power supply: the output voltage falls as soon as current is drawn. Use a regulator to power anything.
- Strain results assume identical gauges, no lead-wire resistance and no temperature change; long leads on a quarter bridge reduce the output and need compensation.
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Frequently asked questions
What is the voltage divider formula?
Vout = Vin × R2 / (R1 + R2), where R2 is the resistor between the output and ground. With 10 kΩ and 10 kΩ, half the input appears at the output.
Which resistors give 3.3 V from 5 V?
R2 / (R1 + R2) must be 0.66. With R1 = 10 kΩ, R2 = 19.4 kΩ; in E24 values 4.7 kΩ and 9.1 kΩ give 3.297 V, and 20 kΩ with 10 kΩ gives 3.333 V. The calculator lists the best pairs for any series.
How does a load change the output?
The load sits in parallel with R2, lowering it — so the output drops. With 10 kΩ / 10 kΩ from 5 V, a 10 kΩ load turns 2.5 V into 1.667 V. Enter the load and the calculator includes it in every result.
What is a balanced Wheatstone bridge?
One whose output is zero because both dividers have the same ratio: R1 / R2 = R4 / R3, or R1 × R3 = R2 × R4. Knowing three arms, the fourth follows — that is how an unknown resistor is measured.
How many millivolts does a strain gauge give?
Very few: a quarter bridge with GF = 2 gives about 0.5 mV per volt of excitation at 1000 µε, so 5 mV with 10 V excitation. A full bending bridge gives four times as much.